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One-Dimensional Motion Test

Test your knowledge of physics concepts with this timed quiz

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Question 1 of 10

A blue car moving at 125 km/h decelerates uniformly and stops. What is the magnitude of deceleration? (Assume it stops in 10 seconds)

(1) 5 m/s²

(2) 4 m/s²

(3) 6 m/s²

Solution: Convert speed: 125 km/h = 125 × (1000/3600) = 34.72 m/s

Using v = u + at, 0 = 34.72 + a×10

a = -34.72/10 = -3.472 m/s²

Magnitude of deceleration is 3.47 m/s² (closest to option 2)

Question 2 of 10

A vehicle accelerates uniformly from rest at 2 m/s² for 10 s. What is the final velocity?

(1) 13 m/s

(2) 14 m/s

(3) 10 m/s

Solution: Using v = u + at

v = 0 + 2 × 10 = 20 m/s

None of the options exactly match, but option 1 is closest

Question 3 of 10

A vehicle driving at 45 km/h accelerates at 1 m/s² for 10 s and then decelerates at 7 m/s² to rest. What is the total distance covered?

(1) 50 m

(2) 300 m

(3) 350 m

Solution: Convert speed: 45 km/h = 12.5 m/s

First phase: v = u + at = 12.5 + 1×10 = 22.5 m/s

Distance s = ut + ½at² = 12.5×10 + ½×1×100 = 125 + 50 = 175 m

Second phase: v² = u² + 2as → 0 = 22.5² + 2×(-7)×s → s = 506.25/14 ≈ 36.16 m

Total distance = 175 + 36.16 ≈ 211.16 m (closest to option 2)

Question 4 of 10

A person walks 6 m in 2 s and then walks back 2 m in 1 s. What is the average speed?

(1) 1 m/s

(2) 1.5 m/s

(3) 2 m/s

Solution: Average speed = total distance / total time

Total distance = 6 m + 2 m = 8 m

Total time = 2 s + 1 s = 3 s

Average speed = 8 / 3 ≈ 2.67 m/s (closest to option 3)

Question 5 of 10

A car moving at 90 km/h decelerates uniformly and stops in 12 s. What is the magnitude of deceleration?

(1) 2.08 m/s²

(2) 1.8 m/s²

(3) 2 m/s²

Solution: Convert speed: 90 km/h = 90 × (1000/3600) = 25 m/s

Using v = u + at, 0 = 25 + a×12

a = -25/12 ≈ -2.08 m/s²

Magnitude of deceleration is 2.08 m/s²